Question

Solve the following inequality:
${\log }^{2}x⩾\log x+2$

Answer 1

${\log }^{2}x\ge \log x+2$

${\log }^{2}x-\log x-2\ge 0$

$(\log x-2)(\log x+1)\ge 0$

$\log xϵ(-\infty ,-1]\bigcup [2,\infty )$

$xϵ(0,\frac{1}{10}]\bigcup [100,\infty )$