Question

Solve the following inequality:
${\log }_{2}x⩽\frac{2}{{\log }_{2}x-1}$

Answer 1

${\log }_2^{2}x-{\log }_{2}x\le 2x>0({\log }_{2}x-2)({\log }_{2}x+1)\le 0{\log }_{2}x\in [-1,2]x\in [\frac{1}{2},4]$