Question

Solve the following inequality:
${\log }_3|3-4x|>2$

Answer 1

$|3-4x|>3^2\pm (3-4x)>9$

$3-4x>9-6>4x\frac{-3}{2}>x$ and $-(3-4x)>94x-3>9x>3$

$x\in (-\infty ,\frac{-3}{2})\cup (3,\infty )$