Solve the following inequality- log3 x - log-3 x - log1-3 x - 6

log x #160; log 3 #160; +2log x #160; log 3 #160; log x #160; log 3 #160; lt;6 2log x lt;6log 3 log x lt;3log 3 ...

You visited us 3 times! Enjoying our articles? Unlock Full Access!

Integration by Partial Fractions

Solve the fol...

Question

Solve the following inequality:
${log}_{3} x + {log}_{\sqrt{3}} x + {log}_{1 / 3} x < 6$

Open in App

Solution

Suggest Corrections

Similar questions

{log}_{3} (x + 2) (x + 4) + {log}_{1 / 3} (x + 2) < \frac{1}{2} {log}_{\sqrt{3}} 7

{log}_{1 / 6} (x^{2} - 3 x + 2) + 1 < 0

{log}_{3} (x + 2) (x + 4) + {log}_{\frac{1}{3}} (x + 2) < \frac{1}{2} {log}_{\sqrt{3}} 7

{log}_{3} ((x + 2) (x + 4)) + {log}_{1 / 3} (x + 2) < \frac{1}{2} {log}_{\sqrt{3}} 7

{log}_{5} (x - 3) + \frac{1}{2} {log}_{5} 3 < \frac{1}{2} {log}_{5} (2 x^{2} - 6 x + 7)

{log}_{3} x + {log}_{\sqrt{3}} x + {log}_{\frac{1}{3}} x < 6.

Join BYJU'S Learning Program