MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Particular Solution of a Differential Equation

Solve the fol...

Question

Solve the following inequality:
${log}_{8} (x^{2} - 4 x + 3) ⩽ 1$

Open in App

Solution

$(x^{2} - 4 x + 3) > 0 (x - 3) (x - 1) > 0 x \in (- \infty, 1) \cup (3, \infty)$
and
$x^{2} - 4 x + 3 \leq 8 x^{2} - 4 x - 5 \leq 0 (x - 5) (x + 1) \leq 0 x \in [- 1, 5]$
Taking intersection, we get
$x \in [- 1, 1) \cup (3, 5]$

Suggest Corrections

thumbs-up

0

Similar questions

Q. Solve the following inequality:

4^{x} - 3 ⩽ 2^{x + 1}

Q. Solve the following inequality:

{(\frac{1}{10})}^{{log}_{x - 3} (x^{2} - 4 x + 3)} ⩾ 1.

Q. Solve the following inequality :

\frac{x - 1}{x^{2} - 4 x + 3} < 1

Q. Solve the following inequality:

\frac{x^{2} + 1}{4 x - 3} > 2

Q. Solve the following equation:

2 {log}_{8} (2 x) + {log}_{8} (x^{2} + 1 - 2 x) = \frac{4}{3}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

General and Particular Solutions of a DE

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Particular Solution of a Differential Equation

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon