Question

Solve the following inequality:
$\sqrt{\frac{3x-2}{2-x}}>1$

Answer 1

$\sqrt{\frac{3x-2}{2-x}}>1$

$\left(\frac{3x-2}{2-x}\right)>1$

$\frac{3x-2}{2-x}-1>0$

$\frac{3x-2-2+x}{2-x}>0$

$\frac{4(x-1)}{-1(x-2)}>0$

$\frac{(x-1)}{(x-2)}<0$

$x\epsilon (1,2)$