MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Functions

Solve the fol...

Question

Solve the following inequality:
$\sqrt{x^{2} + 1} > x - 1.$

Open in App

Solution

$\sqrt{x^{2} + 1} > x - 1$
Squarring both sides
$x^{2} + 1 > x^{2} - 2 x + 1$
$- 2 x < 0$
$x > 0$
$x ϵ (0, \infty)$

Suggest Corrections

thumbs-up

0

Similar questions

Q. Solve the following inequality:

\sqrt{x + \frac{1}{x^{2}}} + \sqrt{x - \frac{1}{x^{2}}} > \frac{2}{x} .

Q. Solve the following inequality:

\sqrt{x^{2} - 1} > x .

Q. Solve the following inequality:

\sqrt{x^{2} + x} > 1 - 2 x .

Q. Solve the following inequality:

1 - x < \sqrt{x^{2} - 2 x} .

Q. Solve the following inequality:

\frac{x^{2} - 1}{x^{2} + x + 1} < 1

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon