Question

Solve the following inequality:
$\sqrt{x+7}<x.$

Answer 1

squaring on both sides we get $x+7=x^2$

$⟹x^2-x-7>0$

$⟹x\in (-\infty ,+\infty )-(\frac{1-\sqrt{29}}{2},\frac{1+\sqrt{29}}{2})$