Question

Solve the following inequality:
$x-1<\sqrt{7-x}.$

Answer 1

$7-x\ge 0$

$x-7\le 0$

$xϵ(-\infty ,7]$

$x-1<\sqrt{7-x}$

Squarring both sides

$x^2-2x+1<7-x$

$x^2-x-6<0$

$(x-3)(x+2)<0$

$xϵ(-2,3)$