Question

Solve the following inequality:
$x+3<\sqrt{x+33}.$

Answer 1

$x+33\ge 0$

$xϵ[-33,\infty )$

$(x+3)<\sqrt{x+33}$

Squarring both sides

$x^2+6x+9<x+33$

$x^2+5x-24<0$

$(x+8)(x-3)<0$

$xϵ(-8,3)$