Question

Solve the following inequality:
$x<\sqrt{2-x}.$

Answer 1

$2-x\ge 0$

$x-2\le 0$

$xϵ(-\infty ,2]$

$x<\sqrt{2-x}$

Squarring both sides

$x^2<2-x$

$x^2+x-2<0$

$(x+2)(x-1)<0$

$xϵ(-2,1)$