Question

Solve the following inequality:
$|x^2-2x-3|<3x-3$

Answer 1

$|x^2-2x-3|<3(x-1)$

$x^2-2x-3>-3(x-1)$

$x^2+x-6>0$

$(x+3)(x-2)>0$

$xϵ(-\infty ,-3)\cup (2,\infty )$

and

$x^2-2x-3<3(x-1)$

$x^{-}5x<0$

$x(x-5)<0$

$xϵ(0,5)$

So, $xϵ(2,5)$