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Question

Solve the following inequality:
|x2+4x|5<0.

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Solution

|x2+4x|5<0
|x2+4x|<5
x2+4x>5
x2+4x+5>0
b<0
xϵR
x2+4x<5
x2+4x5<0
x2+5xx5<0
(x1)(x+5)<0
xϵ(5,1)
So, xϵ(5,1)

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