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Question

Solve the following inequality:
|x24x|<5

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Solution

|x24x|<5
x24x>5
x24x+5>0
b<0
xϵR
and
x24x<5
x24x5<0
x25x+x5<0
(x5)(x+1)<0
xϵ(1,5)
So, xϵ(1,5)

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