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Question

Solve the following inequation : 2y-3 < y+1 4y+7 ,where yR.

A
-2 y 4
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B
-2 y < 4
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C
-2 < y < 4
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D
-2 < y 4
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Solution

The correct option is B -2 y < 4
2y-3 < y+1 4y+7 2y-3 < y+1 and y+1 4y+7
y < 4 and -63y
y < 4 and y -2
-2 y < 4

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