Solve the following inequation: −3<x−2≤9−2x , xϵN.
−1<x≤113
−2<x≤113
−1<x≤103
1<x≤113
−3<x−2≤9−2x,xϵ N⇒−3<x−2 and x−2≤9−2x⇒−x<−2+3 and ⇒x+2x≤9+2⇒−x<1 and ⇒3x≤11⇒x>−1 and ⇒x≤113 So, −1<x≤113