Solve the following inequation and represent the solution set on the number line: $- 2 \frac{2}{3} \leq x + \frac{1}{3} < 3 \frac{1}{3}, x ϵ R$ .
[4 MARKS]

Open in App

Solution

Steps: 2 Marks
Answer: 1 Mark
Solution on number line: 1 Mark

$- 2 \frac{2}{3} \leq x + \frac{1}{3} < 3 \frac{1}{3}, x ϵ R . \Rightarrow \frac{- 8}{3} \leq x + \frac{1}{3} < \frac{10}{3} \Rightarrow \frac{- 8}{3} - \frac{1}{3} \leq x + \frac{1}{3} - \frac{1}{3} < \frac{10}{3} - \frac{1}{3} \Rightarrow \frac{- 9}{3} \leq x < \frac{9}{3} \Rightarrow - 3 \leq x < 3$
Solution set is ${x : x ϵ R, - 3 \leq x < 3}$
On the number line, solution set is:

Suggest Corrections

Similar questions

2 x - 5 \leq 5 x + 4 < 11, w h e r e x ϵ I

- 3 < - \frac{1}{2} - \frac{2 x}{3} \leq \frac{5}{6}, x ϵ R

- 2 \frac{2}{3} \leq x + \frac{1}{3} < 3 \frac{1}{3}; x ϵ R

- 3 (x - 7) \geq 15 - 7 x > \frac{x + 1}{3}, x ϵ R

- 3 + x \leq \frac{8 x}{3} + 2 \leq \frac{14}{3} + 2 x

x ϵ I

13 x - 5 < 15 x + 4 < 7 x + 12, x ϵ R

Join BYJU'S Learning Program