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Byju's Answer
Standard IX
Mathematics
Problems Reducible to Simultaneous Equations
Solve the fol...
Question
Solve the following linear equation.
n
2
−
3
n
4
+
5
n
6
=
21
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Solution
n
2
−
3
n
4
+
5
n
6
=
21
⇒
6
n
−
9
n
+
10
n
12
=
21
⇒
7
n
12
=
21
⇒
n
=
21
×
12
7
⇒
n
=
36
To check:
n
2
−
3
n
4
+
5
n
6
=
21
⇒
36
2
−
3
×
36
4
+
5
×
36
6
=
21
⇒
18
−
27
+
30
=
21
⇒
21
=
21
⇒
L
H
S
.
=
R
.
H
.
S
Therefore, it is correct.
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24
Similar questions
Q.
Solve the following linear equation.
n
2
−
3
n
4
+
5
n
6
=
21
Q.
Question 2
n
2
−
3
n
4
+
5
n
6
=
21
Q.
Solve:
2
3
(
n
+
6
)
−
1
5
(
n
−
4
)
=
3
7
(
n
+
12
)
Q.
Solve
2
3
(
n
+
6
)
−
1
5
(
n
−
4
)
=
3
7
(
n
+
12
)
, then
n
=
.
Q.
Solve the following equation:
3
(
n
−
4
)
+
2
(
4
n
−
5
)
=
5
(
n
+
2
)
+
16
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