Question

Solve the following linear equations:
(a) 4x + 5 = 9
(b) x + $\frac{3}{2}$ = 2x

Answer 1

(a) We have 4x + 5 = 9
⇒ 4x = 9 – 5 (Transposing 5 to RHS)
⇒ 4x = 4
⇒ x = 1 (Dividing by 4 on both sides)
(b) We have x + $\frac{3}{2}$ = 2x
⇒ $\frac{3}{2}$ = 2x – x
⇒ x = $\frac{3}{2}$