Question

Solve the following linear equations: If $\frac{n}{2}-\frac{3n}{4}+\frac{5n}{6}=21$, then $n=$

• A. $19$
• B. $47$
• C. $22$
• D. $36$

Answer 1

The correct option is D $36$

Given, $\frac{n}{2}-\frac{3n}{4}+\frac{5n}{6}=21$

L.C.M. of $2,4,6$ is $12$

$\frac{6n-9n+10n}{12}=21$

$\Rightarrow 7n=21\times 12$

$\Rightarrow n=36$