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Question

Solve the following Linear Programming Problem graphically:
Maximize Z=3x+2y
Subject to x+2y10,3x+y15,x,y0

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Solution

Maximise Z=3x+2y
Subject to
x+2y10,3x+y15,x,y0

x+2y=10
x010y50

3x+y=15
x05y150
Corner pointsValue of Z=3x+2y(5,0)15(4,3)18(0,5)10(0,0)0

Hence, Z=18 is maximum at (4,3).

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