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Question

Solve the following Linear Programming Problem graphically:
Maximize Z=5x+3y
Subject to:
3x+5y15,5x+2y10,
x0,y0

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Solution

Maximize Z=5x+3y
Subject to
3x+5y15,5x+2y10, x0,y0

3x+5y=15
x05y30

5x+2y=10
x02y50
Corner pointsValue of Z=5x+3y(0,3)9(2019,4519)23519(2,0)10

Hence, Z=23519 is maximum at (2019,4519).

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