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Question

Question 75

Solve the following:

mm12=1m23

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Solution

Given, mm12=1m23
2m(m1)2=3(m2)3
3(2mm+1)=2(3m+2) [By cross multiplication]
3(m+1)=2(5m)
3m+3=102m
3m+2m=103
5m=7
m=75


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