wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve the following pair of equations.
4(x+2)+5(y+2)=20 and 5x+4y=7

A
x=7,y=2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
x=4,y=2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
x=3,y=2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
x=2,y=2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B x=3,y=2
4(x+2)+5(y+2)=204x+5y=2 ....(i)
5x+4y=7 ........(ii)
On adding (i) and (ii) , we get
9x+9y=9
x+y=1 ....(iii)
On subtracting (i) from (ii) , we get
xy=5 ....(iv)
On adding (iii) and (iv) , we get
2x=6
x=3
By putting x=3 in (iv), we get
3y=5
y=2
x=3,y=2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Algebraic Solution
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon