wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve the following pair of equations:
ax+by=c
bx+ay=1+c

A
x=acbbcb2a2 and y=bcaacb2a2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
x=ab+baca2b2 and y=bcaacb2a2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
x=acbbca2b2 and y=bcaacb2a2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
x=cbcaa2b2 and y=bcaacb2a2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C x=acbbca2b2 and y=bcaacb2a2
Given equations are,
ax+by=c ....(1)
and bx+ay=1+c ....(2)
Multiply equation (1) by a and equation (2) by b, we get
a2x+aby=ac ....(3)
and b2x+aby=b+bc ....(4)
Subtract equations (3) and (4),
x(a2b2)=acbbc
x=acbbca2b2
Put this value in equation (1), we get
a(acbbca2b2)+by=c
a2cababca2c+b2c=by(a2b2)
b(bcaba)=by(a2b2)
y=bcaacb2a2

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Algebraic Solution
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon