Question

Solve the following pair of equations by method of substitution:
$3x-y-2=0$ and $2x+y-8=0$

Answer 1

Given equations are

$3x-y=2$ ....(1)

and $2x+y=8$ ....(2)

Therefore, $y=3x-2$ ....(3)

Substitute this value of $y$ in equation (2), we get

$2x+3x-2=8$

$\Rightarrow 5x=10$

$\Rightarrow x=2$

Put this value in equation (3),

$y=6-2=4$

Therefore, solution is $x=2$ and $y=4$.