Question

Solve the following pair of Equations by substitution method:
$x-y=1$ and $2x-3y=2$

Answer 1

Given equations are

$x-y=1$ ....(1)

and $2x-3y=2$ ....(2)

Therefore, $x=y+1$ ....(3)

Substitute this value in equation (2), we get

$2(y+1)-3y=2$

$\Rightarrow 2y+2-3y=2$

$\Rightarrow y=0$

Put this value in equation (3),

$x=y+1$

$\Rightarrow x=0+1$

$\Rightarrow x=1$

Therefore, the solution is $x=1,y=0$.