Question

Solve the following pair of equations:
$\frac{x}{3}+\frac{y}{4}=4;x+y=14$

Answer 1

Given equation,

$\frac{x}{3}+\frac{y}{4}=4,x+y=14$

$\Rightarrow 4x+3y=48⟶\left(1\right),4x+4y=56⟶\left(2\right)$

Subtracting equation $\left(1\right)$ and $\left(2\right)$

$4x+3y-48=04x+4y-56=0--------0-y+8=0$

$y=8$

For $y=8,x=6$

$(x,y)=(6,8)$