Question

Solve the following pair of equations $\frac{4}{x}+3y=8;\frac{6}{x}-4y=-5$

Answer 1

Let $\frac{1}{x}$ be u

Then,$\frac{4}{x}+3y=4u+3y=8$ .............................1

and $\frac{6}{x}-4y=6u-4y=-5$ ................................2

Multiplying eq. 1 by 3 and eq. 2 by 2 we get,

$12u+9y=24$ .............3

$12u-8y=-10$ .................4

Solving eq. 3 and eq. 4 by elimination method we get

$y=2$ and $u=\frac{1}{2}$

Therefore$x=2$