Question

Solve the following pair of equations $\frac{2x}{15}+\frac{y}{5}=4;\frac{x}{3}=\frac{y}{2}$

• A. $x=15,y=10$
• B. $x=20,y=10$
• C. $x=5,y=10$
• D. $x=13,y=10$

Answer 1

Answer: (A)

$x=15,y=10$

Given, $\frac{2x}{15}+\frac{y}{5}=4;\frac{x}{3}=\frac{y}{2}$
Rewriting the given equations, we get
$2x+3y=60$ ...(i)
$2x-3y=0$ ...(ii)
On adding (i) and (ii) , we get
$4x=60$
$\Rightarrow x=15$
On putting $x=15$ in (i), we get
$2\left(15\right)+3y=60$
$\Rightarrow y=10$
$\therefore x=15,y=10$