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Question

Solve the following pair of equations:
1x+3y=1
6x12y=2
(where x0,y0)

A
x=35,y=73
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B
x=53,y=152
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C
x=3,y=11
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D
x=4,y=9
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Solution

The correct option is B x=53,y=152
Let 1x=a and 1y=b (As x0,y0)
Then, the given equations become
a+3b=1 …(1)
6a12b=2 …(2)
Multiplying equation (1) by 4, we get 4a+12b=4 …(3)
On adding equation (2) and equation (3), we get 10a=6
a=35
Putting a=35in equation (1), we get
35+3b=1
b=1(35)3
b=215
Hence, x=53 and y=152

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