The correct option is B x=53,y=152
Let 1x=a and 1y=b (As x≠0,y≠0)
Then, the given equations become
a+3b=1 …(1)
6a−12b=2 …(2)
Multiplying equation (1) by 4, we get 4a+12b=4 …(3)
On adding equation (2) and equation (3), we get 10a=6
⇒a=35
Putting a=35in equation (1), we get
35+3b=1
⇒b=1−(35)3
⇒b=215
Hence, x=53 and y=152