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Question

Solve the following pair of equations:
5x1+1y2=2
6x13y2=1
(Where x1,y2)

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Solution

If we substitute 1x1 as p and 1y2 as q in the given equations. (As x1,y2)
We get the equations as
5p+q=2.....(i)
6q3q=1.....(ii)
Now we can solve the pair of equation by method of elimination.Multiply equation (i) by 3
15p+3q=6....(iii)

Adding both (ii) and (iii)
21p=7
p=13
Now by substituting the value of p in (i), we get
5×13+q=2
q=253
q=13
As we have assumed
p=1x1
1x1=13
x=4
Similarly, we assumed
q=1y2
1y2=13
y2=3 or y=5
Thus, x=4, y=5

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