Question

Solve the following pair of equations graphically; $2x-3y=1,$ & $4x-3y+1=0$

• A. $x=1$ $y=-1$
• B. $x=-1$ $y=-1$
• C. $x=-1$ $y=1$
• D. $x=1$ $y=1$

Answer 1

The correct option is B $x=-1$ $y=-1$

Plot each line by taking two points on them.
$2x-3y=1$
$x=0⟹y=\frac{-1}{3}$ and $y=0⟹x=\frac{1}{2}$
Join the two points $(0,\frac{-1}{3})$ and $(\frac{1}{2},0)$ by drawing line.

$4x-3y+1=0$

$x=0⟹y=\frac{-1}{3}$and $y=0⟹x=\frac{1}{4}$

Join the two points $(0,\frac{-1}{3})$ and $(\frac{1}{4},0)$ by drawing line.

From the graph, the point of intersection of both lines is $(-1,-1)$ and hence solution of given system of linear equation is $x=-1,y=-1$