Solve the following pair of equations :
$y = 2 x - 6$
$y = 0$

x = 7; y = 0

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x = - 3; y = 0

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x = 0; y = - 6

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x = 3; y = 0

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Solution

The correct option is D $x = 3; y = 0$
Put $y = 0$ in the 1st equation
$2 x - 6 = 0 ∴ x = 3$

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Similar questions

\frac{2 x + y}{x + y} = \frac{3}{2} a n d \frac{x - y}{2 x - y} = \frac{- 3}{10}, x + y \neq 0, 2 x - y \neq 0

\frac{6}{x + y} = \frac{7}{x - y} + 3

\frac{1}{2 (x + y)} = \frac{1}{3 (x - y)},

x + y \neq 0

x - y \neq 0

x - y = 0

y + 3 = 0

Solve the following pair of equations.

$\frac{7 x - 2 y}{x y} = 5$

$\frac{8 x + 6 y}{x y} = 15$

Here, x $\neq$ 0 and y $\neq$ 0.

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