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Question

# Solve the following pair of linear equations by elimination methodx2+2y3=âˆ’1 and xâˆ’y3=3

A
x=1,y=7
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B
x=2,y=3
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C
x=3,y=3
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D
x=5,y=7
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Solution

## The correct option is D x=2,y=−3Given system of equations are:x2+2y3=−1......(1)x−y3=3................(2)From eq 1 will have⇒3x+4y=−6.........(3)From eq 2 will have ⇒3x−y=9...........(4)Now using elimination method frist we will eliminate y :now multiplying eq 4 from 4 will have⇒12x−4y=36Now from eq 3 and 4 will get x:3x+4y=−612x−4y=36⇒15x=30⇒x=2Now substituting x=2 in eq 2 will get y⇒(2)3−y=9⇒6−y=9⇒−y=9−6⇒y=−3⇒x=2,y=−3

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