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Question

Solve the following pair of linear equations by elimination method
x2+2y3=1 and xy3=3

A
x=1,y=7
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B
x=2,y=3
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C
x=3,y=3
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D
x=5,y=7
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Solution

The correct option is D x=2,y=3
Given system of equations are:
x2+2y3=1......(1)
xy3=3................(2)
From eq 1 will have
3x+4y=6.........(3)
From eq 2 will have
3xy=9...........(4)
Now using elimination method frist we will eliminate y :
now multiplying eq 4 from 4 will have
12x4y=36
Now from eq 3 and 4 will get x:
3x+4y=6
12x4y=36
15x=30
x=2
Now substituting x=2 in eq 2 will get y
(2)3y=9
6y=9
y=96
y=3
x=2,y=3

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