The correct option is C x=0,y=0
√7x+√11y=0 ......(i)
√3x−√5y=0 ......(ii)
On multiplying equation (i) by √3 and equation (ii) by √7. we get,
√21x+√33y=0 ......(iii)
√21x−√35y=0 ......(iv)
On subtracting equation (iv) from equation (iii). we get,
√21x+√33y=0
√21−x−√35+y=0−–––––––––––––––––––
(√33+√35)y=0
⇒y=0
On substituting y=0 in equation (i). we get,
√7x+√11×0=0
⇒√7x=0
⇒x=0
∴x=0,y=0
Option A is correct.