Solve the following pair of linear equations by Substitution method
$2 x - 3 y = 19$ and $3 x - 2 y = 21$ .

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Solution

The equations given to us are:
$2 x - 3 y = 19$ ... $(1)$
$3 x - 2 y = 21$ ... $(2)$

By substitution method, we will substitute the value of $y$ from equation $1$ in equation $2$ .

$∴$ from first equation $y = \frac{(2 x - 19)}{3}$

So by substituting the value of $y$ in the second equation,

The second equation becomes:

$3 x - \frac{2 (2 x - 19)}{3} = 21$

$\Rightarrow \frac{9 x - 4 x + 38}{3} = 21$

$\Rightarrow 5 x = 63 - 38$

$\Rightarrow 5 x = 25$

$\Rightarrow x = 5$

Substituting the value of $x$ in equation number $(1)$ we get ,

$2 (5) - 3 y = 19$

$\Rightarrow 10 - 19 = 3 y$

$\Rightarrow - 9 = 3 y$

$\Rightarrow y = - 3$

then $y$ from above equation will be $- 3$ .

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Similar questions

\sqrt{2} x + \sqrt{3} y = 0

\sqrt{3} x - \sqrt{8} y = 0

Solve the following pairs of linear (simultaneous) equations using method of elimination by substitution:

$3 x + 2 y = 11$

$2 x - 3 y + 10 = 0$

\sqrt{2} x + \sqrt{3} y = 0; \sqrt{3} x - \sqrt{8} y = 0

Solve the pair of linear equations by substituting method:-

√2x+√3y=0

√3x-√8y=0

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