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Question

Solve the following pair of linear equations by substitution method:
8x+5y=12
3x2y=0

A
x=2431 y=3631
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B
x=2431 y=2431
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C
x=3631 y=2431
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D
x=1 y=0
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Solution

The correct option is A x=2431 y=3631

8x+5y=12...........(1)
3x2y=0..............(2)
Multiplying by 8 in (2) and 3 in (1), we get
24x+15y=36
24x16y=0
_____________
31y=36y=3631

Substituting y=3631 in equation (2), we get
3x2y=0
3x2(3631)=03x7231=0

3x=7231x=7231×3
x=2431


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