Solve the following pair of linear equations:
2√x+3√y=2
4√x−9√y=−1
(Where x>0,y>0)
x=4,y=9
The pair of equations are not linear. We will substitute
1x as u2 and 1y as v2 (As x>0,y>0)
Then we will get the equations as
2u+3v=2
4u−9v=−1
We will use method of elimination to solve the equation
6u+9v=6
4u−9v=−1
Adding the above two equations
u=12
Substituting u in above equations, we get v=13
So x=1u2=4
y=1v2=9