Question

Solve the following pair of linear equations

$\frac{2}{\sqrt{x}}$ + $\frac{3}{\sqrt{y}}$ = 2

$\frac{4}{\sqrt{x}}$ - $\frac{9}{\sqrt{y}}$ = -1

• A. 9, 8
• B. 4, 9
• C. 3, 2
• D. 1/2, 1/3

Answer 1

The correct option is B

4, 9

The pair of equations is not linear. We will substitute $\frac{1}{x}$ as $u^2$ and $\frac{1}{y}$ as $v^2$

We get

2u + 3v = 2

4u - 9v = -1

We will use method of elimination to solve the equation

6u + 9v = 6

4u - 9v = -1

Adding the above two equations

u= $\frac{1}{2}$

Substituting u in above equation

v= $\frac{1}{3}$

So x = $\frac{1}{u^2}$= 4

y = $\frac{1}{v^2}$ = 9