Solve the following pair of linear equations in two variables (by graph) :
$(x + 2) (y - 1) = x y, (x - 1) (y + 1) = x y$

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Solution

$(x + 2) (y - 1) = x y (x - 1) (y + 1) = x y$
$x y - x + 2 y - 2 = x y x y + x - y - 1 = x y$
$x - 2 y + 2 = 0 x - y = 1$

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Similar questions

\frac{7 x - 2 y}{x y} = 5

\frac{8 x + 7 y}{x y} = 15

\frac{7 x - 2 y}{x y} = 5, \frac{8 x + 7 y}{x y} = 15

\frac{(x + y)^{2}}{x^{2} y + x y^{2}} = 2; \frac{x^{2} - y^{2}}{x^{2} y + x y^{2}} = 6

\frac{x + y}{x y} = 2, \frac{x - y}{x y} = 6

Solve the following pair of equations.

$\frac{7 x - 2 y}{x y} = 5$

$\frac{8 x + 6 y}{x y} = 15$

Here, x $\neq$ 0 and y $\neq$ 0.

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