Solve the following pair of non-linear equations-4-x-3 y-8- 6-x-4 y-5A- x-2- y-1B- x-1- y-1C- x-1- y-2D- x-2- y-2

The correct option is D x = 2, y = 2Given: 4/x + 3y = 8...(i) 6/x 4y = 5...(ii) Now, (i) ⇒1/x = (8 3y)/4...(iii) (ii) ⇒1/x = ( 5 + 4y)/6...(iv) From (iii ...

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Standard X

Mathematics

Zeroes of a Polynomial

Solve the fol...

Question

Solve the following pair of non-linear equations:
$\frac{4}{x} + 3 y = 8, \frac{6}{x} - 4 y = - 5$

x = 1, y = 2

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x = 2, y = 2

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x = 2, y = 1

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x = 1, y = 1

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Solution

The correct option is B $x = 2, y = 2$
Given:
$\frac{4}{x} + 3 y = 8... (i)$
$\frac{6}{x} - 4 y = - 5... (i i)$

Now,
$(i) \Rightarrow \frac{1}{x} = \frac{(8 - 3 y)}{4} . . . (i i i)$
$(i i) \Rightarrow \frac{1}{x} = \frac{(- 5 + 4 y)}{6} . . . (i v)$

From (iii) and (iv),
$\frac{8 - 3 y}{4} = - \frac{5}{6} + \frac{2 y}{3}$
$\Rightarrow \frac{17 y}{12} = \frac{17}{6}$
$\Rightarrow y = 2....... (v)$

Substituting (v) in (iii) gives $\frac{1}{x} = \frac{1}{2}$
$\Rightarrow x = 2$

Hence, x = y = 2.

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Solve the following pair of linear equations.

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Here, x > 0 and y > 0.

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Solve the following pair of linear equations:
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Solve the following pair of non-linear equations: 4x+3y=8,6x−4y=−5

The correct option is B x=2,y=2Given: 4x+3y=8...(i) 6x−4y=−5...(ii) Now, (i)⇒1x=(8−3y)4...(iii) (ii)⇒1x=(−5+4y)6...(iv) From (iii) and (iv), 8−3y4=−56+2y3 ⇒17y12=176 ⇒y=2.......(v) Substituting (v) in (iii) gives 1x=12 ⇒x=2 Hence, x = y = 2.

Solve the following pair of non-linear equations:
$\frac{4}{x} + 3 y = 8, \frac{6}{x} - 4 y = - 5$