Question

Solve the following pair of simultaneous equations:

$4x+\frac{3}{y}=1;3x-\frac{2}{y}=5$

• A. $x=-6,y=7$
• B. $x=-3,y=1$
• C. $x=1,y=-1$
• D. $x=2,y=0$

Answer 1

Answer: (C)

$x=1,y=-1$

On putting $\frac{1}{y}=Y$, we get

$4x+3Y=1$ ...(i)
$3x-2Y=5$ ...(ii)
On multiplying (i) by 3 and (ii) by 4 and subtracting, we get
$12x+9Y=3$
$\underset{–}{\underset{-}{1}2x\underset{+}{-}8Y=\underset{-}{2}0}$
$17Y=-17$
$\therefore Y=-1$
On putting $Y=-1$ in (i), we get
$4x+3(-1)=1\Rightarrow 4x=4\Rightarrow x=1$
$\therefore x=1,y=\frac{1}{Y}=\frac{1}{-1}=-1$