Question

Solve the following pair of simultaneous equations:

$\frac{a}{4}-\frac{b}{3}=0;\frac{3a+8}{5}=\frac{2b-1}{2}$

• A. $a=-4.5,b=12$
• B. $a=4,b=-5$
• C. $a=14,b=10.5$
• D. $a=12,b=11.5$

Answer 1

The correct option is C $a=14,b=10.5$

$\frac{a}{4}-\frac{b}{3}=0\Rightarrow a=\frac{4b}{3}$

Substituting for '$a$' in the other equation.

$\frac{3a+8}{5}=\frac{2b-1}{2}6a+16=10b-56\ast \frac{4b}{3}+16=10b-58b+16=10b-521=2bb=10.5$

So, $a=\frac{4\times 10.5}{3}=14$

$\therefore a=14,b=10.5$

Option $C$