Solve the following pairs of equations.
$x + y = 5$ ; $x - y = 1$

(3, 2)

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(2, 2)

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(4, 2)

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None of these

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Solution

The correct option is A $(3, 2)$
$x - y = 1$ ....eq1
$x + y = 5$ .....eq2
Add & subtract both the equations, we will get
$2 X = 6$
$⟹ x = 3$ &
Put the value of x in equ 1
$y = 2$

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Similar questions

\frac{5}{x - 1} + \frac{1}{y - 2} = 2

\frac{6}{x - 1} - \frac{3}{y - 2} = 1

x \neq 1, y \neq 2)

Solve the following pair of equations:
$\frac{5}{x - 1} + \frac{1}{y - 2} = 2$
$\frac{6}{x - 1} - \frac{3}{y - 2} = 1$
(where $x \neq 1, y \neq 2)$

\frac{x - 1}{2} + \frac{y + 1}{5} = 4 \frac{1}{5}; \frac{x + y}{3} = y - 1

\frac{25}{x + y} - \frac{3}{x - y} = 1

\frac{40}{x + y} + \frac{2}{x - y} = 5

\frac{5}{x} - \frac{4}{y} = - 2, \frac{2}{x} + \frac{3}{y} = 13

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