Solve the following pairs of equations.
$y = 2 x + 1$ ; $y + 3 x - 6 = 0$

(1, 3)

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(2, 3)

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(4, 3)

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None of these

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Solution

The correct option is A $(1, 3)$
Here given equations are $y - 2 x = 1$ ; $y + 3 x = 6$
Subtract both the equations, we will get $x = 1$ .
On substituting the value of $x$ in any given equations we get $y = 3$

Suggest Corrections

Similar questions

\frac{x - y}{6} = 2

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2 x + y = 3 (x - 4)

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