Solve the following pairs of linear (simultaneous) equations using method of elimination by substitution:

$2 x - 3 y + 6 = 0$

$2 x + 3 y - 18 = 0$

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Solution

2x-3y=-6. (1)
2x+3y=18. (2)

(1) + (2)

2x-3y+2x+3y=-6+18

4x. =12

x = 3

Substituting x=3 in equation 2

We get

6+3y=18

3y=18-6

y=4

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Similar questions

Solve the following pairs of linear equations using the method of elimination by substitution

1) .2x-3y+6=0. 2x+3y-18=0

2 x + 3 y = 8

2 x = 2 + 3 y

2 x + 3 y = 8

2 x = 2 + 3 y

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