Solve the following pairs of linear (simultaneous) equations using method of elimination by substitution:

$6 x = 7 y + 7$

$7 y - x = 8$

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Solution

6x = 7y + 7...(1)

7y - x = 8...(2)

From (2), x = 7y - 8

Putting this value of x in (1)

6(7y - 8) = 7y + 7

42y - 48 = 7y + 7

35y = 55

y=11/7

From (2) x = 11-8

x = 3

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Similar questions

6 x = 7 y + 7

7 y - x = 8

6 x = 7 y + 7

7 y - x = 8

Solve the following pairs of linear (simultaneous) equations using method of elimination by substitution:

$2 x - 3 y = 7$

$5 x + y = 9$

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