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Question

Solve the following pairs of linear (simultaneous) equations using method of elimination by substitution:

x6+y15=4

x3y12=434

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Solution

x6+y15=4(5x+2y)30=45x+2y=1205x=1202yx=(1202y)5x3y12=43413[xy4]=19413[(1202y)5y4]=194(48013y)20=57448013y=28513y=195y=15x=(1202×15)5x=905x=18


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