Solve the following problem by elimination method:2x=5y+4 and 3x-2y+16=0

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Solution

Dear Student,

$2 x = 5 y + 4 S o, x = \frac{5 y + 4}{2} 3 x - 2 y + 16 = 0 3 (\frac{5 y + 4}{2}) - 2 y + 16 = 0 \frac{15 y + 12}{2} - 2 y + 16 = 0 15 y + 12 - 4 y + 32 = 0 11 y + 44 = 0 y = - 4 S o, x = \frac{5 y + 4}{2} = \frac{5 (- 4) + 4}{2} = - 8$
Regards

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Solve the following problem by elimination method:2x=5y+4 and 3x-2y+16=0

Dear Student, 2x=5y+4So, x = 5y+423x-2y+16=03(5y+42)-2y+16=015y+122-2y+16=015y+12-4y+32=011y+44=0y=-4So, x=5y+42 =5(-4)+42 = -8 Regards

Dear Student,

$2 x = 5 y + 4 S o, x = \frac{5 y + 4}{2} 3 x - 2 y + 16 = 0 3 (\frac{5 y + 4}{2}) - 2 y + 16 = 0 \frac{15 y + 12}{2} - 2 y + 16 = 0 15 y + 12 - 4 y + 32 = 0 11 y + 44 = 0 y = - 4 S o, x = \frac{5 y + 4}{2} = \frac{5 (- 4) + 4}{2} = - 8$
Regards