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Question

Solve the following problem by elimination method:2x=5y+4 and 3x-2y+16=0

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Solution

Dear Student,

2x=5y+4So, x = 5y+423x-2y+16=03(5y+42)-2y+16=015y+122-2y+16=015y+12-4y+32=011y+44=0y=-4So, x=5y+42 =5(-4)+42 = -8
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